Fungsi f : r → r dan g : r → r. diketahui : f(x) = 2x – 3 dan g(x) = x2 + 2x – 3. nilai dari (f o g) (2) = ........ 0 b. 1 c. 7 d. 8 e. 11
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Penjelasan dengan langkah-langkah:
f(x) = 2x-3
g(x) = x²-2x-3
(f°g)(x) = f(g(x))
= f (x²-2x-3)
= 2(x²-2x-3)-3
= 2x²-4x-6-3
= 2x²-4x-9
X=2
(f°g)(2)= 2(2)²-4(2)-9
= 2(4) - 8 - 9
= 8 - 8 -9
= -9
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